Why power lines run at high voltage
The wires on the tall steel towers carry hundreds of thousands of volts — far more than anything in a house needs. The reason is a square: loss in a wire grows with the current squared, and raising the voltage is how you shrink the current.
Power is a product
Voltage is the push on the electric charge, measured in volts. Current is how much charge flows per second, measured in amperes. Multiply them and you get power, the rate energy is delivered, in watts: P = V × I. A city that needs a fixed amount of power can get it many ways: a big push and a small flow, or a small push and a big flow. The product is the same. The wire does not care about the product. It cares about the flow.
Why it matters
Every real wire has resistance, a measure of how hard it is to push current through it, in ohms. Current forced through resistance makes heat, and that heat is energy that left the power station and never reached anyone. Across the United States, transmission and distribution together lose about 5% of the electricity sent, averaged over 2018 to 2022. At low voltage the same wire would waste far more (set the slider below to 10 kV and see).
Why the loss goes as the square
Ohm's law says the voltage dropped along a resistor is current times resistance: Vdrop = I R. That drop is a small slice of the line voltage, not the whole of it; V²/R with the full transmission voltage would describe a short circuit, not a working line. The power turned into heat in that resistor is the dropped voltage times the current. Put the two together and the heat is Ploss = I² R. The current appears twice, once as the flow and once as the push it takes to maintain that flow, so it enters as a square.
Now hold the delivered power fixed and raise the transmission voltage ten times. Because P = V I, the current falls ten times. Because the loss is I² R, it falls a hundred times. Raise the voltage a hundred times and the loss falls ten thousand times. The wire is the same wire; only the split between push and flow has changed.
Interactive Drag the voltage slider from 10 kV to 1 MV and watch the current fall and the wire cool; the two dashed marks on the chart sit exactly 10× apart in voltage.
There is a second, smaller benefit. A thinner wire has more resistance, and the loss is proportional to R. Cutting the current a hundredfold lets you tolerate a wire with far more resistance for the same heat, so the conductors can be lighter and cheaper.
Two honest caveats. Real grids run mostly on alternating current, and an alternating line has other effects beyond plain resistance, so the resistive loss is a floor, not the whole story. And high voltage is dangerous near people, which is why transformers step it down at substations before it reaches a street. The high-voltage part of the grid is the long-haul part: generated above 10 kV, sent long distances at over 200 kV, and reduced in stages to the 120 or 240 V at a wall socket.
In short
Delivered power is voltage times current, but the heat wasted in a wire is current squared times resistance. For a fixed delivery, every tenfold rise in voltage cuts the current tenfold and the wasted heat a hundredfold. That is the whole reason the wires on the towers run at hundreds of thousands of volts: not to push harder, but to flow less.
Where this comes from
- How much electricity is lost in electricity transmission and distribution in the United States? (FAQ) linked only, not reproduced
www.eia.gov/tools/faqs/faq.php?id=105&t=3 - College Physics 2e, §20.4 Electric Power and Energy linked only, not reproduced
openstax.org/books/college-physics-2e/pages/20-4-electric-power-and-energy - College Physics 2e, §23.7 Transformers linked only, not reproduced
openstax.org/books/college-physics-2e/pages/23-7-transformers